$A$ triangle has two fixed vertices $A(a, 0)$ and $B(0, b)$. Let its third vertex $C$ move along the line $x = y$. If $s$ is the area of triangle $ABC$, then $\frac{ds}{dx} =$

  • A
    $a + b$
  • B
    $-\frac{a + b}{2}$
  • C
    $\frac{a - b}{2}$
  • D
    $\frac{a + b}{2}$

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