int frac{dx}{x log x log(log x)} = | vedclass

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Question

(B) Let $I = \int \frac{dx}{x \log x \log(\log x)}$.Substitute $\log x = t$. Then,$\frac{1}{x} dx = dt$.The integral becomes $\int \frac{dt}{t \log t}

Vedclass · Accepted Answer

$\log[\log(\log x)] + c$

Vedclass · Answer

(B) Let $I = \int \frac{dx}{x \log x \log(\log x)}$.Substitute $\log x = t$. Then,$\frac{1}{x} dx = dt$.The integral becomes $\int \frac{dt}{t \log t}$.Now,substitute $\log t = z$. Then,$\frac{1}{t} dt = dz$.The integral becomes $\int \frac{dz}{z} = \log|z| + c$.Substituting back the values,we get $\log|\log t| + c = \log|\log(\log x)| + c$.

$\int \frac{dx}{x \log x \log(\log x)} = $

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