$\int_0^{2a} \frac{f(x)}{f(x) + f(2a - x)} \, dx = $

  • A
    $a$
  • B
    $\frac{a}{2}$
  • C
    $2a$
  • D
    $0$

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Similar Questions

मान लीजिए $g_i: \left[\frac{\pi}{8}, \frac{3\pi}{8}\right] \rightarrow \mathbb{R}, i=1, 2$,और $f: \left[\frac{\pi}{8}, \frac{3\pi}{8}\right] \rightarrow \mathbb{R}$ ऐसे फलन हैं कि $g_1(x)=1, g_2(x)=|4x-\pi|$ और $f(x)=\sin^2 x$,सभी $x \in \left[\frac{\pi}{8}, \frac{3\pi}{8}\right]$ के लिए।
$S_i = \int_{\frac{\pi}{8}}^{\frac{3\pi}{8}} f(x) \cdot g_i(x) dx, i=1, 2$ को परिभाषित करें।
$(1)$ $\frac{16S_1}{\pi}$ का मान है।
$(2)$ $\frac{48S_2}{\pi^2}$ का मान है।

$\int_0^\pi {{e^{{{\cos }^2}x}}{{\cos }^5}3x} \,dx$ का मान है

समाकलन $\sum\limits_{k = 1}^n {\int_0^1 {f(k - 1 + x)\,dx} } $ का मान क्या है?

Difficult
View Solution

$\int_{0}^{\frac{\pi}{2}} \frac{\sin^{\frac{2}{3}} x}{\sin^{\frac{2}{3}} x + \cos^{\frac{2}{3}} x} dx =$

$\int_{-\pi / 2}^{\pi / 2} \frac{\cos x}{1+e^{x}} d x$ का मान ज्ञात कीजिए।

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