Regarding the two isotopes _{13}Al^{27} and _ | vedclass

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Question

(C) For $_{13}Al^{27}$: Number of protons $(Z)$ = $13$,Mass number $(A)$ = $27$. Number of neutrons = $A - Z = 27 - 13 = 14$. For $_{14}Si^{27}$: Numb

Vedclass · Accepted Answer

Both isotopes have a mass number of $27$.

Vedclass · Answer

(C) For $_{13}Al^{27}$: Number of protons $(Z)$ = $13$,Mass number $(A)$ = $27$. Number of neutrons = $A - Z = 27 - 13 = 14$. For $_{14}Si^{27}$: Number of protons $(Z)$ = $14$,Mass number $(A)$ = $27$. Number of neutrons = $A - Z = 27 - 14 = 13$. Both species have the same mass number $(A = 27)$,so they are isobars. Option $C$ is correct because both have a mass number of $27$.

Regarding the two isotopes $_{13}Al^{27}$ and $_{14}Si^{27}$,which of the following statements is correct?

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