(B) The temperatures are $T_{1} = 627 + 273 = 900 \text{ K}$ and $T_{2} = 27 + 273 = 300 \text{ K}$.Efficiency $\eta = 1 - \frac{T_{2}}{T_{1}} = 1 - \

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(B) The temperatures are $T_{1} = 627 + 273 = 900 \text{ K}$ and $T_{2} = 27 + 273 = 300 \text{ K}$.Efficiency $\eta = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{300}{900} = 1 - \frac{1}{3} = \frac{2}{3}$.Heat absorbed $Q_{1} = 3 \times 10^{6} \text{ cal} = 3 \times 10^{6} \times 4.2 \text{ J} = 12.6 \times 10^{6} \text{ J}$.Work done $W = \eta \times Q_{1} = \frac{2}{3} \times 12.6 \times 10^{6} \text{ J} = 8.4 \times 10^{6} \text{ J}$.

Class 11 Physics Thermodynamics Heat Engine and Carnot Cycle

Medium

$A$ Carnot engine absorbs $3 \times 10^{6} \text{ cal}$ of heat from a reservoir at $627^{\circ}C$ and rejects it at $27^{\circ}C$. The work done by the engine is:

A
$4.2 \times 10^{6} \text{ J}$
B
$8.4 \times 10^{6} \text{ J}$
C
$16.8 \times 10^{6} \text{ J}$
D
Zero

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Class 11

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Thermodynamics

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Heat Engine and Carnot Cycle

In a Carnot engine,if the temperatures of the source and the sink are decreased by $100 \ K$ each,then the efficiency of the engine:

MediumAP EAMCET 2023

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When the temperature difference between the source and sink increases,the efficiency of the heat engine

EasyAP EAMCET 2020

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$A$ Carnot engine is made to work between $200^{\circ}C$ and $0^{\circ}C$ first and then between $0^{\circ}C$ and $-200^{\circ}C$. The ratio of efficiencies of the engine in the two cases is

Medium

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$A$ Carnot engine whose sink is at $300\, K$ has an efficiency of $40\%.$ By how much should the temperature of the source be increased so as to increase its efficiency by $50\%$ of its original efficiency? (in $K$)

DifficultAIPMT 2006

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When the absolute temperature of the source of a Carnot heat engine is increased by $25 \%$,its efficiency increases by $80 \%$. The new efficiency of the engine is (in $\%$)

EasyAP EAMCET 2016

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$A$ Carnot engine absorbs $3 \times 10^{6} \text{ cal}$ of heat from a reservoir at $627^{\circ}C$ and rejects it at $27^{\circ}C$. The work done by the engine is:

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In a Carnot engine,if the temperatures of the source and the sink are decreased by $100 \ K$ each,then the efficiency of the engine:

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