Which of the following will have the lowest v | vedclass

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(B) The lowering of vapor pressure is a colligative property,which depends on the number of particles (van't Hoff factor $i$ $	imes$ moles of solute)

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$1\% NaCl$

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(B) The lowering of vapor pressure is a colligative property,which depends on the number of particles (van't Hoff factor $i$ $	imes$ moles of solute).For $1\%$ solutions,we calculate the relative number of particles:$1\%$ Sucrose $(C_{12}H_{22}O_{11})$: $i=1$,moles = $1/342 \approx 0.0029$$1\% NaCl$: $i=2$,moles = $1/58.5 \approx 0.0342$$1\% CaCl_2$: $i=3$,moles = $1/111 \approx 0.0090 	imes 3 = 0.0270$$1\%$ Glucose $(C_6H_{12}O_6)$: $i=1$,moles = $1/180 \approx 0.0055$Since $1\% NaCl$ has the highest number of particles,it will cause the maximum lowering of vapor pressure,resulting in the lowest vapor pressure.

Which of the following will have the lowest vapor pressure?

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