How much energy in $kJ$ is required to heat $5 \, kg$ of water from $20^oC$ to its boiling point? (Specific heat of water = $4.2 \, kJ \, kg^{-1} \, ^oC^{-1}$)

Water of mass $5 \ kg$ in a closed vessel is at a temperature of $20^{\circ} C$. If the temperature of the water when heated for a time of $10 \ minutes$ becomes $30^{\circ} C$, then the increase in the internal energy of the water is (Specific heat capacity of water $= 4200 \ J \ kg^{-1} \ K^{-1}$) (in $kJ$)

If some heat is given to a metal of mass $100 \ g$,its temperature rises by $20^{\circ} C$. If the same heat is given to $20 \ g$ of water,the change in its temperature (in $^{\circ} C$) is (The ratio of specific heat capacities of metal and water is $1: 10$).

When $300 \, J$ of heat is given to a body of mass $25 \, g$,its temperature rises from $25^{\circ}C$ to $45^{\circ}C$. What are the heat capacity and specific heat capacity,respectively?

The amount of heat required to raise the temperature of a body by $1^oC$ is called its

Derive the equation for the molar specific heat capacity of solids.