What will be the conductivity of a pure silic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The conductivity $\sigma$ of an intrinsic semiconductor is given by the formula: $\sigma = n_i e (\mu_n + \mu_p)$.Here,$n_i = 1.072 	imes 10^{10}

Vedclass · Accepted Answer

$3.14 	imes 10^{-6} \ mho/cm$

Vedclass · Answer

(D) The conductivity $\sigma$ of an intrinsic semiconductor is given by the formula: $\sigma = n_i e (\mu_n + \mu_p)$.Here,$n_i = 1.072 	imes 10^{10} \ cm^{-3}$,$e = 1.6 	imes 10^{-19} \ C$,$\mu_n = 1350 \ cm^2/(V \cdot s)$,and $\mu_p = 480 \ cm^2/(V \cdot s)$.Substituting the values:$\sigma = (1.072 	imes 10^{10}) 	imes (1.6 	imes 10^{-19}) 	imes (1350 + 480)$$\sigma = (1.072 	imes 1.6 	imes 10^{-9}) 	imes (1830)$$\sigma = 1.7152 	imes 10^{-9} 	imes 1830$$\sigma \approx 3.1388 	imes 10^{-6} \ mho/cm \approx 3.14 	imes 10^{-6} \ mho/cm$.

What will be the conductivity of a pure silicon crystal at $300 \ K$? Given that the intrinsic carrier concentration is $1.072 \times 10^{10} \ cm^{-3}$ and at this temperature,the electron mobility $\mu_n = 1350 \ cm^2 / (V \cdot s)$ and hole mobility $\mu_p = 480 \ cm^2 / (V \cdot s)$.

Similar Questions

The contribution in the total current flowing through a semiconductor due to electrons and holes are $\frac{3}{4}$ and $\frac{1}{4}$ respectively. If the drift velocity of electrons is $\frac{5}{2}$ times that of holes at this temperature,then the ratio of concentration of electrons and holes is

$A$ semiconductor doped with a donor impurity is

To obtain electrons as majority charge carriers in a semiconductor,the impurity mixed is

If $n_e$ and $v_d$ are the number of electrons and drift velocity in a semiconductor, respectively, what happens when the temperature is increased?

When the conductivity of a semiconductor is only due to breaking of covalent bonds, the semiconductor is called

Vedclass Test Series

Exam Paper Generator

Online Exam Module