In an $N-P-N$ transistor amplifier,the collector current is $9 \ mA$. If $90\%$ of the electrons emitted from the emitter reach the collector,then:

  • A
    $\alpha = 0.9$ and $\beta = 9.0$
  • B
    Base current is $10 \ mA$
  • C
    Emitter current is $1 \ mA$
  • D
    $\alpha = 0.99$ and $\beta = 99.0$

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