In a common emitter (CE) amplifier having a v | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The voltage gain $A_{V}$ of a common emitter amplifier is given by the formula $A_{V} = g_{m} R_{L}$,where $g_{m}$ is the transconductance and $R_

Vedclass · Accepted Answer

$\frac{2}{3}\,G$

Vedclass · Answer

(B) The voltage gain $A_{V}$ of a common emitter amplifier is given by the formula $A_{V} = g_{m} R_{L}$,where $g_{m}$ is the transconductance and $R_{L}$ is the load resistance.For the first transistor: $A_{V1} = G = g_{m1} R_{L} = 0.03 	imes R_{L}$.For the second transistor: $A_{V2} = g_{m2} R_{L} = 0.02 	imes R_{L}$.Taking the ratio of the two gains:$\frac{A_{V2}}{A_{V1}} = \frac{g_{m2} R_{L}}{g_{m1} R_{L}} = \frac{g_{m2}}{g_{m1}}$.Substituting the given values:$\frac{A_{V2}}{G} = \frac{0.02}{0.03} = \frac{2}{3}$.Therefore,the new voltage gain is $A_{V2} = \frac{2}{3} G$.

In a common emitter $(CE)$ amplifier having a voltage gain $G$,the transistor used has a transconductance of $0.03\,mho$ and a current gain of $25$. If the above transistor is replaced with another one with a transconductance of $0.02\,mho$ and a current gain of $20$,the new voltage gain will be:

Similar Questions

In an $n-p-n$ transistor,$10^{8}$ electrons enter the emitter in $10^{-8} \,s$. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor $\beta$ are respectively:

Which of the following regions of transistors are,respectively,heavily doped and lightly doped?

In a common emitter configuration, a transistor has $\beta=50$ and input resistance $1 \text{ k}\Omega$. If the peak value of a.c. input is $0.01 \text{ V}$, then the peak value of collector current is: (in $\mu\text{A}$)

$A$ transistor is operated in common emitter configuration at $V_C = 2 \, V$ such that a change in the base current from $100 \, \mu A$ to $300 \, \mu A$ produces a change in the collector current from $10 \, mA$ to $20 \, mA$. The current gain is

In the given circuit, a voltmeter $V$ is connected across a bulb $B$. If the value of the resistor $R$ is increased, what happens?

Vedclass Test Series

Exam Paper Generator

Online Exam Module