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(A) The current due to electrons in a semiconductor is given by $I_e = n_e A e v_e$.The current due to holes is given by $I_h = n_h A e v_h$.Taking th

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$5/4$

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(A) The current due to electrons in a semiconductor is given by $I_e = n_e A e v_e$.The current due to holes is given by $I_h = n_h A e v_h$.Taking the ratio of the currents:$\frac{I_e}{I_h} = \frac{n_e A e v_e}{n_h A e v_h} = \frac{n_e}{n_h} 	imes \frac{v_e}{v_h}$.Given that $\frac{n_e}{n_h} = 7/5$ and $\frac{I_e}{I_h} = 7/4$.Substituting these values:$\frac{7}{4} = \frac{7}{5} 	imes \frac{v_e}{v_h}$.Solving for the ratio of drift velocities:$\frac{v_e}{v_h} = \frac{7}{4} 	imes \frac{5}{7} = \frac{5}{4}$.

If the ratio of the number density of electrons to the number density of holes in a semiconductor is $7/5$ and the ratio of their currents is $7/4$,what is the ratio of their drift velocities?

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