How many necklaces can be formed by selecting $4$ beads from $6$ different colored glass beads and $4$ beads from $5$ different colored metal beads?

  • A
    $^6P_4 \times ^5P_4 \times \frac{7!}{2!}$
  • B
    $^6C_4 \times ^5C_4 \times \frac{7!}{2!}$
  • C
    $^6C_4 \times ^5C_4 \times \frac{8!}{2!}$
  • D
    $^6C_4 \times ^5C_4 \times 7!$

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