There are n distinct points on a circle. If t | vedclass

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(B) The number of pentagons that can be formed using $n$ points is given by the combination formula $\binom{n}{5}$.The number of triangles that can be

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$8$

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(B) The number of pentagons that can be formed using $n$ points is given by the combination formula $\binom{n}{5}$.The number of triangles that can be formed using $n$ points is given by $\binom{n}{3}$.According to the problem,the number of pentagons is equal to the number of triangles:$\binom{n}{5} = \binom{n}{3}$.Using the property of combinations,if $\binom{n}{r} = \binom{n}{k}$,then either $r = k$ or $r + k = n$.Since $5 
eq 3$,we must have $n = 5 + 3$.Therefore,$n = 8$.

There are $n$ distinct points on a circle. If the number of pentagons that can be formed using these points as vertices is equal to the number of triangles that can be formed,then the value of $n$ is:

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