If vec{a}, vec{b}, vec{c} are non-coplanar ve | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $\vec{\alpha} = \vec{a} + 2\vec{b} + 3\vec{c}$,$\vec{\beta} = \lambda\vec{b} + 4\vec{c}$,and $\vec{\gamma} = (2\lambda - 1)\vec{c}$.The vector

Vedclass · Accepted Answer

For all values of $\lambda$ except two values

Vedclass · Answer

(C) Let $\vec{\alpha} = \vec{a} + 2\vec{b} + 3\vec{c}$,$\vec{\beta} = \lambda\vec{b} + 4\vec{c}$,and $\vec{\gamma} = (2\lambda - 1)\vec{c}$.The vectors are non-coplanar if their scalar triple product is non-zero,i.e.,$[\vec{\alpha}, \vec{\beta}, \vec{\gamma}] 
eq 0$.$[\vec{\alpha}, \vec{\beta}, \vec{\gamma}] = \begin{vmatrix} 1 & 2 & 3 \ 0 & \lambda & 4 \ 0 & 0 & (2\lambda - 1) \end{vmatrix} [\vec{a}, \vec{b}, \vec{c}]$$= 1 \cdot \lambda \cdot (2\lambda - 1) [\vec{a}, \vec{b}, \vec{c}] = \lambda(2\lambda - 1) [\vec{a}, \vec{b}, \vec{c}]$Since $\vec{a}, \vec{b}, \vec{c}$ are non-coplanar,$[\vec{a}, \vec{b}, \vec{c}] 
eq 0$.Thus,the vectors are non-coplanar if $\lambda(2\lambda - 1) 
eq 0$.This implies $\lambda 
eq 0$ and $\lambda 
eq \frac{1}{2}$.Therefore,the vectors are non-coplanar for all values of $\lambda$ except two values,$0$ and $\frac{1}{2}$.

If $\vec{a}, \vec{b}, \vec{c}$ are non-coplanar vectors and $\lambda$ is a real number,then for what value of $\lambda$ are the vectors $\vec{a} + 2\vec{b} + 3\vec{c}$,$\lambda\vec{b} + 4\vec{c}$,and $(2\lambda - 1)\vec{c}$ non-coplanar?

Similar Questions

If $a, b, c$ are three coplanar vectors,then $[a + b, b + c, c + a] = $

$\vec{a}=2 \hat{i}-\hat{j}$, $\vec{b}=2 \hat{j}-\hat{k}$, $\vec{c}=2 \hat{k}-\hat{i}$ are three vectors and $\vec{d}$ is a unit vector perpendicular to $\vec{c}$. If $\vec{a}, \vec{b}, \vec{d}$ are coplanar vectors, then $|\vec{d} \cdot \vec{b}|=$

If $\bar{a}+\bar{b}, \bar{b}+\bar{c}, \bar{c}+\bar{a}$ are coterminous edges of a parallelepiped,then its volume is

If $\overrightarrow{a} \cdot \overrightarrow{b} = 1, \overrightarrow{b} \cdot \overrightarrow{c} = 2$ and $\overrightarrow{c} \cdot \overrightarrow{a} = 3$,then the value of $[\vec{a} \times(\vec{b} \times \vec{c}), \vec{b} \times(\vec{c} \times \vec{a}), \vec{c} \times(\vec{b} \times \vec{a})]$ is

If the vectors $ai + j + k$,$i + bj + k$,and $i + j + ck$ $(a \ne 1, b \ne 1, c \ne 1)$ are coplanar,then the value of $\frac{1}{1 - a} + \frac{1}{1 - b} + \frac{1}{1 - c} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module