Let $\vec{a} = \hat{j} - \hat{k}$ and $\vec{c} = \hat{i} - \hat{j} - \hat{k}$. If $\vec{a} \times \vec{b} + \vec{c} = \vec{0}$ and $\vec{a} \cdot \vec{b} = 3$,find the vector $\vec{b}$.

  • A
    $-\hat{i} + \hat{j} - 2\hat{k}$
  • B
    $2\hat{i} - \hat{j} + 2\hat{k}$
  • C
    $\hat{i} - \hat{j} - 2\hat{k}$
  • D
    $\hat{i} + \hat{j} - 2\hat{k}$

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Let $\vec{a}, \vec{b}$ and $\vec{c}$ be three non-zero vectors such that no two of them are collinear and $(\vec{a} \times \vec{b}) \times \vec{c} = \frac{1}{3}|\vec{b}| |\vec{c}| \vec{a}$. If $\theta$ is the angle between vectors $\vec{b}$ and $\vec{c}$,then a value of $\sin \theta$ is:

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