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(B) For two quadratic equations $a_1x^2 + b_1x + c_1 = 0$ and $a_2x^2 + b_2x + c_2 = 0$,if the roots are in the same ratio,then $\frac{b_1^2}{b_2^2} =

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$2/9$

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(B) For two quadratic equations $a_1x^2 + b_1x + c_1 = 0$ and $a_2x^2 + b_2x + c_2 = 0$,if the roots are in the same ratio,then $\frac{b_1^2}{b_2^2} = \frac{a_1c_1}{a_2c_2}$.Given equations are $x^2 + 3x + 2 = 0$ and $x^2 - x + \lambda = 0$.Here,$a_1 = 1, b_1 = 3, c_1 = 2$ and $a_2 = 1, b_2 = -1, c_2 = \lambda$.Substituting these values in the formula:$\frac{3^2}{(-1)^2} = \frac{1 	imes 2}{1 	imes \lambda}$$\frac{9}{1} = \frac{2}{\lambda}$$9\lambda = 2$$\lambda = \frac{2}{9}$

If the roots of the equations $x^2 + 3x + 2 = 0$ and $x^2 - x + \lambda = 0$ are in the same ratio,then what is the value of $\lambda$?

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