If one card is drawn at random from a pack of | vedclass

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(C) Let $A$ be the event of drawing a king and $B$ be the event of drawing a spade.Total number of cards $n(S) = 52$.Number of kings $n(A) = 4$.Number

Vedclass · Accepted Answer

$4/13$

Vedclass · Answer

(C) Let $A$ be the event of drawing a king and $B$ be the event of drawing a spade.Total number of cards $n(S) = 52$.Number of kings $n(A) = 4$.Number of spades $n(B) = 13$.Number of cards that are both a king and a spade $n(A \cap B) = 1$.Using the addition theorem of probability: $P(A \cup B) = P(A) + P(B) - P(A \cap B)$.$P(A \cup B) = \frac{4}{52} + \frac{13}{52} - \frac{1}{52}$.$P(A \cup B) = \frac{4 + 13 - 1}{52} = \frac{16}{52}$.Simplifying the fraction,we get $P(A \cup B) = \frac{4}{13}$.

If one card is drawn at random from a pack of $52$ cards,what is the probability that it is a king or a spade?

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