If $A$ and $B$ are two independent events,then $P(A \cup B) = $
- A$P(A) + P(B) - P(A)P(B)$
- B$P(A) - P(B)$
- C$P(A) + P(B)$
- D$P(A) + P(B) + P(A)P(B)$
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Similar Questions
If two events $E_1$ and $E_2$ are such that $P(E_1 \cup E_2) = \frac{5}{8}$, $P(\bar{E}_1) = \frac{3}{4}$, and $P(E_2) = \frac{1}{2}$, then $E_1$ and $E_2$ are:
What is the probability of drawing either a queen or a red card from a deck of $52$ cards?
Medium
View SolutionGiven that the events $A$ and $B$ are such that $P(A) = \frac{1}{2}$,$P(A \cup B) = \frac{3}{5}$,and $P(B) = p$. Find $p$ if the events $A$ and $B$ are independent.
Easy
View SolutionIf $E$ and $F$ are events such that $P(E)=\frac{1}{4}$,$P(F)=\frac{1}{2}$ and $P(E \cap F)=\frac{1}{8}$,find $P(\text{not } E \text{ and not } F)$.
Easy
View SolutionOne card is drawn randomly from a pack of $52$ cards. The probability that it is a king or a spade is:
Medium
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