Find the median of the sequence ^{2n}C_0, ^{2 | vedclass

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(B) The sequence is $^{2n}C_0, ^{2n}C_1, ^{2n}C_2, \dots, ^{2n}C_n$.The number of terms in the sequence is $n + 1$.Since $n$ is even,$n + 1$ is odd.Th

Vedclass · Accepted Answer

$^{2n}C_{\frac{n}{2}}$

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(B) The sequence is $^{2n}C_0, ^{2n}C_1, ^{2n}C_2, \dots, ^{2n}C_n$.The number of terms in the sequence is $n + 1$.Since $n$ is even,$n + 1$ is odd.The median of a sequence with an odd number of terms $N$ is the term at position $\frac{N+1}{2}$.Here,$N = n + 1$,so the median is the term at position $\frac{(n+1)+1}{2} = \frac{n+2}{2} = \frac{n}{2} + 1$.The term at position $\frac{n}{2} + 1$ in the sequence $^{2n}C_0, ^{2n}C_1, \dots, ^{2n}C_n$ is $^{2n}C_{n/2}$.

$x_i$	$5$	$15$	$25$	$35$	$45$	$55$
$f_i$	$12$	$18$	$27$	$20$	$17$	$6$

Find the median of the sequence $^{2n}C_0, ^{2n}C_1, ^{2n}C_2, \dots, ^{2n}C_n$ (where $n$ is even).

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