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Question

(D) For the emission of photoelectrons from a surface, the wavelength of the incident light $\lambda$ must be  <  or equal to the threshold wavelength

Vedclass · Accepted Answer

Both $(A)$ and $(B)$

Vedclass · Answer

(D) For the emission of photoelectrons from a surface, the wavelength of the incident light $\lambda$ must be  Given, $\lambda_0 = 5200\, 	ext{\AA}$.Ultraviolet light has a wavelength range typically between $100\, 	ext{\AA}$ and $4000\, 	ext{\AA}$, which is  Infrared light has a wavelength greater than $7000\, 	ext{\AA}$, which is greater than $5200\, 	ext{\AA}$.Therefore, light from an ultraviolet lamp (regardless of power, as power only affects the number of photoelectrons, not the emission condition) will cause emission.Thus, both $(A)$ and $(B)$ are correct.

The threshold wavelength for the emission of photoelectrons from a material is $5200\, \text{\AA}$. Which of the following monochromatic light sources will cause the emission of photoelectrons from this surface?

Similar Questions

For alkali metals, threshold frequencies lie in which region?

Which of the following statements is correct?

Assertion : Kinetic energy of photoelectrons emitted by a photosensitive surface depends upon the intensity of incident photon.
Reason : The ejection of electrons from a metallic surface is possible with a frequency of incident photon below the threshold frequency.

The value of threshold frequency depends on which of the following factors?

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