In the photoelectric effect,assuming the ener | vedclass

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(C) The photoelectric current is proportional to the number of photoelectrons emitted per unit time,which is equal to the number of incident photons p

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does not depend on the photon frequency but depends only on the intensity of the incident beam.

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(C) The photoelectric current is proportional to the number of photoelectrons emitted per unit time,which is equal to the number of incident photons per unit time (assuming one photon ejects one electron).The number of photons incident per unit time is given by $\frac{dn}{dt} = \frac{P}{E}$,where $P$ is the power of the incident beam and $E = h
u$ is the energy of a single photon.Since power $P = I 	imes A$ (where $I$ is intensity and $A$ is area),we have $\frac{dn}{dt} = \frac{IA}{h
u}$.The photoelectric current $i$ is proportional to the rate of emission of electrons: $i \propto \frac{dn}{dt} = \frac{IA}{h
u}$.However,in the standard photoelectric effect,the number of photoelectrons emitted depends only on the number of incident photons (intensity) provided the frequency is above the threshold frequency. The frequency $
u$ affects the kinetic energy of the electrons,not the number of electrons emitted per unit time for a fixed intensity $I$. Therefore,the photoelectric current is independent of the frequency $
u$ and depends only on the intensity $I$ of the incident light.

In the photoelectric effect,assuming the energy of a photon is proportional to its frequency and is completely absorbed by an electron in the metal,the photoelectric current...

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