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Question

(C) Einstein's photoelectric equation is given by $K_{max} = h
u - \phi_0$,where $K_{max}$ is the maximum kinetic energy,$h$ is Planck's constant,$

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(C) Einstein's photoelectric equation is given by $K_{max} = h
u - \phi_0$,where $K_{max}$ is the maximum kinetic energy,$h$ is Planck's constant,$
u$ is the frequency of incident radiation,and $\phi_0 = h
u_0$ is the work function of the metal.This equation is of the form $y = mx + c$,where $y = K_{max}$,$x = 
u$,$m = h$ (slope),and $c = -\phi_0$ (y-intercept).Since the y-intercept is negative $(-\phi_0)$,the graph starts from the x-axis at a frequency $
u = 
u_0$ (threshold frequency) and increases linearly with a positive slope $h$. Thus,the graph has a positive x-intercept at $
u_0$.

According to Einstein's photoelectric equation,the graph between the kinetic energy of emitted photoelectrons and the frequency of incident radiation is:

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