A radio station broadcasts at a wavelength of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Wavelength $\lambda = 300 \ m$,Power $P = 10 \ kW = 10^4 \ W$.Energy of one photon $E = \frac{hc}{\lambda}$.The number of photons emitted p

Vedclass · Accepted Answer

$1.5 	imes 10^{31}$

Vedclass · Answer

(B) Given: Wavelength $\lambda = 300 \ m$,Power $P = 10 \ kW = 10^4 \ W$.Energy of one photon $E = \frac{hc}{\lambda}$.The number of photons emitted per second $n = \frac{P}{E} = \frac{P \lambda}{hc}$.Substituting the values: $n = \frac{10^4 	imes 300}{6.63 	imes 10^{-34} 	imes 3 	imes 10^8}$.$n = \frac{3 	imes 10^6}{19.89 	imes 10^{-26}} \approx 0.1508 	imes 10^{32} = 1.508 	imes 10^{31}$.Thus,the number of photons emitted per second is approximately $1.5 	imes 10^{31}$.

$A$ radio station broadcasts at a wavelength of $300 \ m$. If the radiating power of the transmitter is $10 \ kW$,then the number of photons emitted per second is:

Similar Questions

The principle of $LASER$ action involves:

What should be the velocity of an electron so that its momentum becomes equal to that of a photon of wavelength $5200 \, \mathring{A}$? (Given: $h = 6.63 \times 10^{-34} \, J \cdot s$, $m_e = 9.1 \times 10^{-31} \, kg$)

There are $n_1$ photons of frequency $\nu_1$ in a beam of light. In an equally energetic beam,there are $n_2$ photons of frequency $\nu_2$. Then the correct relation is

The wavelength of a $1 \;keV$ photon is $1.24 \times 10^{-9} \;m$. What is the frequency of a $1 \;MeV$ photon?

$A$ photon of $1.7 \times 10^{-13} \ J$ is absorbed by a material under special circumstances. The correct statement is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module