Arrange the following substances in the increasing order of the oxidation number of $Mn$: $MnCl_2, MnO_2, Mn(OH)_3, KMnO_4$.
- A$MnCl_2 < MnO_2 < Mn(OH)_3 < KMnO_4$
- B$MnO_2 < MnCl_2 < Mn(OH)_3 < KMnO_4$
- C$Mn(OH)_3 < MnCl_2 < MnO_2 < KMnO_4$
- D$MnCl_2 < Mn(OH)_3 < MnO_2 < KMnO_4$
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