$C_6H_5NH_2 \xrightarrow{H_2SO_4, 180^{\circ}C} H_2NC_6H_4(SO_3H)$ (para). Which statement is correct for the product?

  • A
    It does not exist as a zwitterion.
  • B
    $-NH_2$ shows strong basic character.
  • C
    It does not act as an internal salt.
  • D
    $-SO_3H$ diminishes the basic character of $-NH_2$.

Explore More

Similar Questions

The major product obtained in the following reaction is:

Identify the major product from the following reaction sequence.

The correct increasing order of basic strength for the following compounds is:

$CH_3-CH_2-CH(CH_3)-CONH_2$ $\xrightarrow[ \Delta ]{ Br_2/KOH } (A)$ $\xrightarrow[ (2) AgOH/\Delta ]{ (1) CH_3I (excess) } (B)$. The major product $(B)$ is:

Difficult
View Solution

$C_6H_5CH_2Cl$ $\xrightarrow{\text{Alc. } NH_3} A$ $\xrightarrow{2 CH_3Cl} B$. The product $B$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo