What is the product formed when RCH = CH_2 is | vedclass

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(C) The reaction of an alkene with $B_2H_6$ followed by oxidation with alkaline $H_2O_2$ is known as Hydroboration-Oxidation. This reaction follows th

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$RCH_2CH_2OH$

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(C) The reaction of an alkene with $B_2H_6$ followed by oxidation with alkaline $H_2O_2$ is known as Hydroboration-Oxidation. This reaction follows the Anti-Markovnikov rule,where the $OH$ group is added to the less substituted carbon atom. The reaction proceeds as follows: $RCH = CH_2 + B_2H_6$ $\rightarrow (RCH_2CH_2)_3B$ $\xrightarrow{H_2O_2/OH^-} RCH_2CH_2OH$. Thus,the product is a primary alcohol,$RCH_2CH_2OH$.

What is the product formed when $RCH = CH_2$ is treated with $B_2H_6$ followed by oxidation with alkaline $H_2O_2$?

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