Which of the following compounds is optically | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For an allene $(R_1R_2C = C = CR_3R_4)$ to be optically active,the groups attached to each terminal carbon must be different,i.e.,$R_1 
eq R_2$ a

Vedclass · Accepted Answer

$CH_2 = C = CH_2$

Vedclass · Answer

(B) For an allene $(R_1R_2C = C = CR_3R_4)$ to be optically active,the groups attached to each terminal carbon must be different,i.e.,$R_1 
eq R_2$ and $R_3 
eq R_4$.$(A)$ $CH_3 - CH = C = CH - CH_3$: Here,$R_1 = CH_3, R_2 = H$ and $R_3 = CH_3, R_4 = H$. Since $R_1 
eq R_2$ and $R_3 
eq R_4$,it is optically active.$(B)$ $CH_2 = C = CH_2$: Here,$R_1 = R_2 = H$. Since the terminal carbons have identical groups,it possesses a plane of symmetry and is optically inactive.$(C)$ $Cl(Br)C = C = C(Cl)Br$: Here,$R_1 = Cl, R_2 = Br$ and $R_3 = Cl, R_4 = Br$. Although the terminal carbons have different groups,the molecule has a plane of symmetry (the plane containing the central carbon and the substituents),making it optically inactive.$(D)$ $Me(Et)C = C = C(Cl)Br$: Here,$R_1 = Me, R_2 = Et$ and $R_3 = Cl, R_4 = Br$. Since $R_1 
eq R_2$ and $R_3 
eq R_4$,it is optically active.Note: In many standard contexts,$CH_2 = C = CH_2$ is the simplest example of an optically inactive allene. However,option $C$ is also optically inactive due to its symmetry. Given the typical nature of such questions,$B$ is the most fundamental answer.

Which of the following compounds is optically inactive?

Similar Questions

What is the absolute configuration of the given molecule?

Identify the optically active substance from the following.

Which compound is chiral?

The number of optical isomers possible for $2-$Bromo$-3-$chlorobutane are

Chirality of a carbon compound is because of its

Vedclass Test Series

Exam Paper Generator

Online Exam Module