In the complex cis-[Cr(en)_2Cl_2]^+,the oxida | vedclass

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(C) The complex is $[Cr(en)_2Cl_2]^+$. Let the oxidation state of $Cr$ be $x$.$x + 2(0) + 2(-1) = +1$$x - 2 = +1 \Rightarrow x = +3$.$Cr$ is a $3d$ tr

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$+3, 3d$ and $6$

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(C) The complex is $[Cr(en)_2Cl_2]^+$. Let the oxidation state of $Cr$ be $x$.$x + 2(0) + 2(-1) = +1$$x - 2 = +1 \Rightarrow x = +3$.$Cr$ is a $3d$ transition metal,so its valence shell involves $3d$ orbitals.The ligand $en$ (ethylenediamine) is bidentate (coordination number $2$) and $Cl^-$ is monodentate (coordination number $1$).Coordination number $= 2(2) + 2(1) = 4 + 2 = 6$.Thus,the values are $+3, 3d$ and $6$.

In the complex $cis-[Cr(en)_2Cl_2]^+$,the oxidation state of $Cr$,the type of $d$-orbital involved in the valence shell,and the coordination number are respectively:

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