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(A) Given the parametric equations of the circle:$x = -7 + 4 \cos 	heta$$y = 3 + 4 \sin 	heta$Rearranging the terms:$x + 7 = 4 \cos 	heta$$y - 3 =

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$(x + 7)^2 + (y - 3)^2 = 16$

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(A) Given the parametric equations of the circle:$x = -7 + 4 \cos 	heta$$y = 3 + 4 \sin 	heta$Rearranging the terms:$x + 7 = 4 \cos 	heta$$y - 3 = 4 \sin 	heta$Squaring both sides and adding them:$(x + 7)^2 + (y - 3)^2 = (4 \cos 	heta)^2 + (4 \sin 	heta)^2$$(x + 7)^2 + (y - 3)^2 = 16 \cos^2 	heta + 16 \sin^2 	heta$$(x + 7)^2 + (y - 3)^2 = 16(\cos^2 	heta + \sin^2 	heta)$Since $\cos^2 	heta + \sin^2 	heta = 1$,we get:$(x + 7)^2 + (y - 3)^2 = 16$

Find the Cartesian equation of the circle whose parametric equations are $x = -7 + 4 \cos \theta$ and $y = 3 + 4 \sin \theta$.

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