If the line x + y - 1 = 0 is tangent to the p | vedclass

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(B) The given line is $x + y - 1 = 0$,which can be written as $y = -x + 1$. Comparing this with the slope-intercept form $y = mx + c$,we have $m = -1$

Vedclass · Accepted Answer

$-4$

Vedclass · Answer

(B) The given line is $x + y - 1 = 0$,which can be written as $y = -x + 1$. Comparing this with the slope-intercept form $y = mx + c$,we have $m = -1$ and $c = 1$.The condition for the line $y = mx + c$ to be tangent to the parabola $y^2 = 4ax$ is $c = \frac{a}{m}$.Here,the parabola is $y^2 = kx$,so $4a = k$,which implies $a = \frac{k}{4}$.Substituting the values into the condition $c = \frac{a}{m}$:$1 = \frac{k/4}{-1}$$1 = -\frac{k}{4}$$k = -4$.

If the line $x + y - 1 = 0$ is tangent to the parabola $y^2 = kx$,find the value of $k$.

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