If the Cartesian coordinates of a point are ( | vedclass

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(C) Given Cartesian coordinates $(x, y) = (\sqrt{3}, 1)$.To find polar coordinates $(r, 	heta)$,we use the relations $x = r \cos 	heta$ and $y = r \

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$(2, \pi/6)$

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(C) Given Cartesian coordinates $(x, y) = (\sqrt{3}, 1)$.To find polar coordinates $(r, 	heta)$,we use the relations $x = r \cos 	heta$ and $y = r \sin 	heta$.First,calculate $r = \sqrt{x^2 + y^2} = \sqrt{(\sqrt{3})^2 + 1^2} = \sqrt{3 + 1} = \sqrt{4} = 2$.Next,calculate $	heta = 	an^{-1}(\frac{y}{x}) = 	an^{-1}(\frac{1}{\sqrt{3}})$.Since both $x$ and $y$ are positive,the point lies in the first quadrant,so $	heta = \frac{\pi}{6}$.Thus,the polar coordinates are $(2, \frac{\pi}{6})$.

If the Cartesian coordinates of a point are $(\sqrt{3}, 1)$,find its polar coordinates.

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