The y-intercept of a line is twice its x-inte | vedclass

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(A) Let the $x$-intercept be $a$. Then the $y$-intercept is $2a$.The intercept form of the line equation is $\frac{x}{a} + \frac{y}{2a} = 1$.Since the

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$2x + y = 4$

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(A) Let the $x$-intercept be $a$. Then the $y$-intercept is $2a$.The intercept form of the line equation is $\frac{x}{a} + \frac{y}{2a} = 1$.Since the line passes through the point $(1, 2)$,we substitute $x = 1$ and $y = 2$ into the equation:$\frac{1}{a} + \frac{2}{2a} = 1$$\frac{1}{a} + \frac{1}{a} = 1$$\frac{2}{a} = 1 \implies a = 2$.Substituting $a = 2$ back into the intercept form equation:$\frac{x}{2} + \frac{y}{4} = 1$Multiplying the entire equation by $4$,we get:$2x + y = 4$.

The $y$-intercept of a line is twice its $x$-intercept. If the line passes through the point $(1, 2)$,find its equation.

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