Find the equation of the bisectors of the ang | vedclass

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(A) The given equation is $2x^{2} - 7xy + 3y^{2} = 0$.Comparing this with $ax^{2} + 2hxy + by^{2} = 0$,we have $a = 2$,$2h = -7 \implies h = -7/2$,and

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$7x^{2} - 2xy - 7y^{2} = 0$

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(A) The given equation is $2x^{2} - 7xy + 3y^{2} = 0$.Comparing this with $ax^{2} + 2hxy + by^{2} = 0$,we have $a = 2$,$2h = -7 \implies h = -7/2$,and $b = 3$.The equation of the bisectors of the angles between the lines is given by the formula:$\frac{x^{2} - y^{2}}{a - b} = \frac{xy}{h}$Substituting the values:$\frac{x^{2} - y^{2}}{2 - 3} = \frac{xy}{-7/2}$$\frac{x^{2} - y^{2}}{-1} = \frac{2xy}{-7}$$7(x^{2} - y^{2}) = 2xy$$7x^{2} - 7y^{2} = 2xy$$7x^{2} - 2xy - 7y^{2} = 0$.

Find the equation of the bisectors of the angles between the lines represented by the equation $2x^{2} - 7xy + 3y^{2} = 0$.

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