A straight line passes through the point A(3, | vedclass

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(B) Let the intercepts of the line on the $x$-axis and $y$-axis be $a$ and $b$ respectively. The equation of the line is $\frac{x}{a} + \frac{y}{b} =

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$4x + 3y = 24$

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(B) Let the intercepts of the line on the $x$-axis and $y$-axis be $a$ and $b$ respectively. The equation of the line is $\frac{x}{a} + \frac{y}{b} = 1$. Since the point $A(3, 4)$ bisects the segment intercepted between the axes,the coordinates of $A$ are $(\frac{a}{2}, \frac{b}{2})$. Equating the coordinates,we get $\frac{a}{2} = 3 \Rightarrow a = 6$ and $\frac{b}{2} = 4 \Rightarrow b = 8$. Substituting these values into the intercept form equation: $\frac{x}{6} + \frac{y}{8} = 1$. Multiplying by $24$,we get $4x + 3y = 24$.

$A$ straight line passes through the point $A(3, 4)$ such that the portion of the line intercepted between the axes is bisected at $A$. Find the equation of the line.

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