If 2x + y + lambda = 0 is a focal chord of th | vedclass

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(B) The given equation of the parabola is $y^2 = -8x$. Comparing this with the standard form $y^2 = -4ax$,we get $4a = 8$,which implies $a = 2$. The f

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$4$

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(B) The given equation of the parabola is $y^2 = -8x$. Comparing this with the standard form $y^2 = -4ax$,we get $4a = 8$,which implies $a = 2$. The focus of the parabola $y^2 = -4ax$ is at $(-a, 0)$. Substituting $a = 2$,the focus is at $(-2, 0)$. Since $2x + y + \lambda = 0$ is a focal chord,it must pass through the focus $(-2, 0)$. Substituting $x = -2$ and $y = 0$ into the equation of the chord: $2(-2) + 0 + \lambda = 0$ $-4 + \lambda = 0$ $\lambda = 4$.

If $2x + y + \lambda = 0$ is a focal chord of the parabola $y^2 = -8x$,find the value of $\lambda$.

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