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(A) Given: Initial angular velocity $\omega_1 = 0 \, rad/s$, Final angular velocity $\omega_2 = 20 \, rad/s$, Time $t = 5 \, s$.First, calculate the a

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$25/\pi \, rev$

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(A) Given: Initial angular velocity $\omega_1 = 0 \, rad/s$, Final angular velocity $\omega_2 = 20 \, rad/s$, Time $t = 5 \, s$.First, calculate the angular acceleration $\alpha$ using the formula $\omega_2 = \omega_1 + \alpha t$:$\alpha = \frac{\omega_2 - \omega_1}{t} = \frac{20 - 0}{5} = 4 \, rad/s^2$.Next, calculate the total angular displacement $	heta$ using $	heta = \omega_1 t + \frac{1}{2} \alpha t^2$:$	heta = 0 + \frac{1}{2} 	imes 4 	imes (5)^2 = 2 	imes 25 = 50 \, rad$.Since $1 \, revolution = 2\pi \, rad$, the number of revolutions $n$ is given by:$n = \frac{	heta}{2\pi} = \frac{50}{2\pi} = \frac{25}{\pi} \, revolutions$.

How many revolutions must a wheel complete to attain an angular velocity of $20 \, rad/s$ in $5 \, s$ starting from rest?

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