What is the maximum acceleration of the train | vedclass

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(B) The acceleration is given by the slope of the speed-time graph.For segment $AB$: $a_1 = \frac{20 - 0}{0.75 - 0} = \frac{20}{0.75} \approx 26.67 \

Vedclass · Accepted Answer

$160$

Vedclass · Answer

(B) The acceleration is given by the slope of the speed-time graph.For segment $AB$: $a_1 = \frac{20 - 0}{0.75 - 0} = \frac{20}{0.75} \approx 26.67 \ km \ h^{-2}$.For segment $BC$: $a_2 = 0 \ km \ h^{-2}$ (constant speed).For segment $CD$: $a_3 = \frac{60 - 20}{1.25 - 1.00} = \frac{40}{0.25} = 160 \ km \ h^{-2}$.For segment $DE$: $a_4 = \frac{0 - 60}{2.00 - 1.25} = \frac{-60}{0.75} = -80 \ km \ h^{-2}$.Comparing these values,the maximum acceleration is $160 \ km \ h^{-2}$.

What is the maximum acceleration of the train during the journey in $km \ h^{-2}$?

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