An iron rod of cross-sectional area 2 times 1 | vedclass

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Question

(B) The magnetic flux density $B$ is given by the ratio of magnetic flux $\phi$ to the cross-sectional area $A$:$B = \frac{\phi}{A} = \frac{6.28 	ime

Vedclass · Accepted Answer

$1.25 	imes 10^4$

Vedclass · Answer

(B) The magnetic flux density $B$ is given by the ratio of magnetic flux $\phi$ to the cross-sectional area $A$:$B = \frac{\phi}{A} = \frac{6.28 	imes 10^{-4} \ Wb}{2 	imes 10^{-5} \ m^2} = 31.4 \ T$The relationship between magnetic flux density $B$,permeability $\mu$,and magnetizing field intensity $H$ is $B = \mu H$.Therefore,the permeability $\mu$ is:$\mu = \frac{B}{H} = \frac{31.4 \ T}{2000 \ A/m} = 0.0157 \ T \cdot m/A$However,calculating the relative permeability $\mu_r$ using $\mu = \mu_0 \mu_r$:$\mu_r = \frac{\mu}{\mu_0} = \frac{0.0157}{4\pi 	imes 10^{-7}} \approx 1.25 	imes 10^4$Thus,the magnetic permeability $\mu$ is approximately $1.25 	imes 10^4 \ \mu_0$.

An iron rod of cross-sectional area $2 \times 10^{-5} \ m^2$ is subjected to a magnetizing field intensity of $2000 \ A/m$. If the magnetic flux produced in the rod is $6.28 \times 10^{-4} \ Wb$,what is the magnetic permeability of the rod?

Similar Questions

$A$ bar of iron having magnetic moment $2.4 \text{ Am}^2$ weighs $66 \text{ g}$. If the density of the material of the bar is $7700 \text{ kg/m}^3$,the intensity of magnetisation in $\text{Am}^{-1}$ is

If the magnetizing field on a ferromagnetic material is increased,its permeability

$A$ material of $0.25 \ cm^2$ cross-sectional area is placed in a magnetic field of strength $(H) 1000 \ Am^{-1}$. Then,the magnetic flux produced is (Susceptibility of material is $313$) (Permeability of free space,$\mu_0 = 4 \pi \times 10^{-7} \ Hm^{-1}$)

Which of the following relations is incorrect?
$(a) \ B = \mu_0(H + I)$
$(b) \ B = \mu_0(H + \chi_m)$
$(c) \ \mu_r = 1 + \chi_m$
$(d) \ \chi_m = I / H$
(Here,$I =$ intensity of magnetization and $H =$ magnetising field)

By putting a magnetic substance of volume $30\, cm^3$ in a magnetising field of strength $\frac{1250}{\pi} \, A/m$,the value of the produced magnetic moment is $6\, A\cdot m^2$. Calculate the value of magnetic induction produced in the substance in $T$.

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