When a current of $4 A$ at $50 Hz$ is passed through a coil,the power consumed by the coil is $240 W$. If the voltage of the $AC$ source is $100 V$,what is the inductance of the coil?

In an $LCR$ series circuit,if $V$ is the effective value of the applied voltage,$V_R$ is the voltage across $R$,and $V_L$ and $V_C$ are the effective voltages across $L$ and $C$ respectively,then:

In an $L-C-R$ circuit,the potential difference across the inductor is $60\,V$,across the capacitor is $30\,V$,and across the resistor is $40\,V$. The supply voltage will be: (in $,V$)

An $AC$ voltage source of variable angular frequency $\omega$ and fixed amplitude $V_0$ is connected in series with a capacitance $C$ and an electric bulb of resistance $R$ (inductance zero). When $\omega$ is increased,

When $100\, V$ $DC$ is applied across a solenoid,a current of $1\, A$ flows in it. When $100\, V$ $AC$ is applied across the same coil,the current drops to $0.5\, A$. If the frequency of the $AC$ source is $50\, Hz$,the impedance and inductance of the solenoid are:

In the circuit shown below,the $ac$ source has voltage $V = 20\cos (\omega t)$ volts with $\omega = 2000 \,rad/sec$. The amplitude of the current will be nearest to: