In the given reaction,what will be A and B re | vedclass

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(A) The reaction of acetone $(CH_3)_2CO$ with $NaCN/HCl$ is a nucleophilic addition reaction forming a cyanohydrin.$A = (CH_3)_2C(OH)CN$ (Acetone cyan

Vedclass · Accepted Answer

$(CH_3)_2C(OH)CN, (CH_3)_2C(OH)COOH$

Vedclass · Answer

(A) The reaction of acetone $(CH_3)_2CO$ with $NaCN/HCl$ is a nucleophilic addition reaction forming a cyanohydrin.$A = (CH_3)_2C(OH)CN$ (Acetone cyanohydrin).Subsequent acid-catalyzed hydrolysis of the cyanohydrin $(A)$ converts the $-CN$ group into a $-COOH$ group.$B = (CH_3)_2C(OH)COOH$ ($2$-hydroxy$-2-$methylpropanoic acid).Therefore,the correct sequence is $A = (CH_3)_2C(OH)CN$ and $B = (CH_3)_2C(OH)COOH$.

In the given reaction,what will be $A$ and $B$ respectively?
$(CH_3)_2CO$ $\xrightarrow{NaCN/HCl} A$ $\xrightarrow{H_3O^+} B$

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In the given reaction,what will be $A$ and $B$ respectively?$(CH_3)_2CO$ $\xrightarrow{NaCN/HCl} A$ $\xrightarrow{H_3O^+} B$