(A) When a glass slab of thickness $t$ and refractive index $\mu$ is placed in the path of a converging beam of light,the rays are refracted towards t

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(A) When a glass slab of thickness $t$ and refractive index $\mu$ is placed in the path of a converging beam of light,the rays are refracted towards the normal at the first surface and away from the normal at the second surface.This causes the point of convergence to shift in the direction of the incident light.The formula for the normal shift is given by $\Delta x = t \left(1 - \frac{1}{\mu}\right)$.Since the shift occurs in the direction of the light propagation,the convergence point moves away from the glass slab,i.e.,further from the original point $P$.

Class 12 Physics Ray Optics and Optical Instruments Refraction through Plane Surface and Glass Slab

Medium

$A$ paraxial beam of light is converging towards a point $P$ on the screen. $A$ plane parallel sheet of glass of thickness $t$ and refractive index $\mu$ is introduced in the path of the beam. The convergence point is shifted by:

A
$t (1 - 1/\mu)$ away
B
$t (1 + 1/\mu)$ away
C
$t (1 - 1/\mu)$ nearer
D
$t (1 + 1/\mu)$ nearer

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Class 12 Questions

Class 12

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Ray Optics and Optical Instruments

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Refraction through Plane Surface and Glass Slab

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$A$ paraxial beam of light is converging towards a point $P$ on the screen. $A$ plane parallel sheet of glass of thickness $t$ and refractive index $\mu$ is introduced in the path of the beam. The convergence point is shifted by:

Similar Questions

The figure shows a transparent slab of length $1 \, m$ placed in air,whose refractive index in the $x$-direction varies as $\mu = 1 + x^2$ for $0 \leq x \leq 1$. The optical path length of ray $R$ will be:

Pick out the wrong statement from the following:

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