A ring of mass M and radius R sliding with a | vedclass

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(C) $1$. When the ring enters the rough surface,a kinetic frictional force $f = \mu Mg$ acts on the ring in the direction opposite to its velocity $v_

Vedclass · Accepted Answer

The angular momentum of the ring is conserved about any point on the horizontal surface.

Vedclass · Answer

(C) $1$. When the ring enters the rough surface,a kinetic frictional force $f = \mu Mg$ acts on the ring in the direction opposite to its velocity $v_0$.$2$. Since an external force (friction) acts on the ring,the linear momentum is not conserved.$3$. The frictional force exerts a torque about the centre of mass $(CM)$ of the ring,causing it to rotate. Therefore,the angular momentum about the $CM$ is not conserved.$4$. The frictional force acts at the point of contact with the surface. If we choose any point on the horizontal surface as the reference point,the line of action of the frictional force passes through this point. Thus,the torque due to friction about any point on the horizontal surface is zero. Consequently,the angular momentum of the ring is conserved about any point on the horizontal surface.$5$. Since friction is a non-conservative force,it does work on the system,so the mechanical energy is not conserved.

$A$ ring of mass $M$ and radius $R$ sliding with a velocity $v_0$ suddenly enters a rough surface where the coefficient of friction is $\mu$,as shown in the figure. Choose the correct statement$(s)$.

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