$(p \wedge \sim q) \wedge (\sim p \vee q)$ is :-

  • A
    $A$ contradiction
  • B
    $A$ tautology
  • C
    Either $(A)$ or $(B)$
  • D
    Neither $(A)$ nor $(B)$

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Similar Questions

If the truth value of $[(p \lor q) \land (q \to r) \land (\sim r)] \to (p \land q)$ is false, then which of the following is $NOT$ true?

Which of the following is not a tautology?

Consider the following statement patterns:
$A$. $(q \to p) \vee (p \to q)$
$B$. $(\sim p \vee \sim q) \leftrightarrow \sim (p \wedge q)$
$C$. $[(p \vee q) \wedge \sim p] \wedge \sim q$
$D$. $(p \wedge q) \wedge (\sim p \vee \sim q)$
Which of the following is correct?

The negation of the statement "If an integer is greater than $4$ and less than $5$, then it is a multiple of $3$" is:

The negation of the statement "The triangle is an equilateral or isosceles triangle and the triangle is not isosceles and it is right angled" is

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