A 4, cm cube is cut into 1, cm cubes. What is | vedclass

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(A) The volume of the large cube is $V_L = 4^3 = 64\, cm^3$.The volume of one small cube is $V_s = 1^3 = 1\, cm^3$.The number of small cubes obtained

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$4:1$

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(A) The volume of the large cube is $V_L = 4^3 = 64\, cm^3$.The volume of one small cube is $V_s = 1^3 = 1\, cm^3$.The number of small cubes obtained is $n = \frac{64}{1} = 64$.The surface area of the large cube is $A_L = 6 	imes (4)^2 = 6 	imes 16 = 96\, cm^2$.The surface area of one small cube is $A_s = 6 	imes (1)^2 = 6\, cm^2$.The total surface area of $64$ small cubes is $A_{total} = 64 	imes 6 = 384\, cm^2$.The ratio of the total surface area of small cubes to the surface area of the large cube is $\frac{384}{96} = 4:1$.

$A$ $4\, cm$ cube is cut into $1\, cm$ cubes. What is the ratio of the total surface area of all the small cubes to the surface area of the large cube?

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