A body moves with velocity v = ln x , m/s whe | vedclass

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(D) According to Newton's Second Law,the net force $F$ acting on a body is given by $F = m \cdot a$,where $a$ is the acceleration.Acceleration is defi

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$x = 1 \, m$

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(D) According to Newton's Second Law,the net force $F$ acting on a body is given by $F = m \cdot a$,where $a$ is the acceleration.Acceleration is defined as the rate of change of velocity with respect to time: $a = \frac{dv}{dt}$.Given the velocity $v = \ln x$,we use the chain rule to express acceleration in terms of position $x$:$a = \frac{dv}{dt} = \frac{dv}{dx} \cdot \frac{dx}{dt} = \frac{d}{dx}(\ln x) \cdot v$.Since $\frac{d}{dx}(\ln x) = \frac{1}{x}$ and $v = \ln x$,we have:$a = \frac{1}{x} \cdot \ln x = \frac{\ln x}{x}$.The net force is zero when $F = m \cdot a = 0$. Since $m 
eq 0$,we must have $a = 0$:$\frac{\ln x}{x} = 0$.This implies $\ln x = 0$,which gives $x = e^0 = 1 \, m$.Therefore,the net force acting on the body is zero at $x = 1 \, m$.

$A$ body moves with velocity $v = \ln x \, m/s$ where $x$ is its position. The net force acting on the body is zero at

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