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(A) The bullet is moving downwards. Let the downward direction be negative. The initial velocity is $u = -100\,m/s$.The acceleration due to gravity is

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(A) The bullet is moving downwards. Let the downward direction be negative. The initial velocity is $u = -100\,m/s$.The acceleration due to gravity is $g = 10\,m/s^2$ downwards,so $a = -10\,m/s^2$.The velocity at any time $t$ (for $0 \le t \le 10\,s$) is given by $v = u + at = -100 - 10t$.At $t = 0\,s$,$v = -100\,m/s$.At $t = 10\,s$,$v = -100 - 10(10) = -200\,m/s$.After $t = 10\,s$,the bullet hits the ground and comes to rest,so $v = 0$ for $10\,s The graph starts at $-100\,m/s$,decreases linearly to $-200\,m/s$ at $t = 10\,s$,and then stays at $0$ from $t = 10\,s$ to $t = 20\,s$. This corresponds to the graph in option $A$.

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