A common emitter amplifier has a voltage gain | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The voltage gain $(A_v)$ of an amplifier is given by the product of the current gain $(\beta)$ and the ratio of output impedance $(R_{	ext{out}})

Vedclass · Accepted Answer

$1250$

Vedclass · Answer

(B) The voltage gain $(A_v)$ of an amplifier is given by the product of the current gain $(\beta)$ and the ratio of output impedance $(R_{	ext{out}})$ to input impedance $(R_{	ext{in}})$:$A_v = \beta 	imes \frac{R_{	ext{out}}}{R_{	ext{in}}}$Given $A_v = 50$,$R_{	ext{in}} = 100\; \Omega$,and $R_{	ext{out}} = 200\; \Omega$,we can find the current gain $(\beta)$:$50 = \beta 	imes \frac{200}{100}$$50 = \beta 	imes 2$$\beta = 25$The power gain $(A_p)$ is defined as the product of the current gain $(\beta)$ and the voltage gain $(A_v)$:$A_p = \beta 	imes A_v$$A_p = 25 	imes 50 = 1250$

$A$ common emitter amplifier has a voltage gain of $50$,an input impedance of $100\; \Omega$,and an output impedance of $200\; \Omega$. The power gain of the amplifier is:

Similar Questions

Which of these is a unipolar transistor?

In a common emitter amplifier,a.c. current gain is $40$ and input resistance is $2 \ k\Omega$. The load resistance is given as $10 \ k\Omega$. Then the voltage gain is

In an $NPN$ transistor,the collector current is $10\, mA$. If $90\%$ of the electrons emitted reach the collector,then:

$A$ common-emitter amplifier is designed with a $n-p-n$ transistor $(\alpha = 0.99)$. The input impedance is $1\, k\Omega$ and load is $10\, k\Omega$. The voltage gain will be

In an $npn$ transistor, $10^{10}$ electrons enter the emitter in $10^{-6} \; s$. If $4\%$ of the electrons are lost in the base, the current transfer ratio $(\alpha)$ will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module