A compound of molecular formula C_8H_8O_2 rea | vedclass

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Question

(A) The molecular formula $C_8H_8O_2$ corresponds to $p$-methoxybenzaldehyde $(CH_3OC_6H_4CHO)$.$1$. It contains an aldehyde group without $\alpha$-hy

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$4-$methoxybenzaldehyde

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(A) The molecular formula $C_8H_8O_2$ corresponds to $p$-methoxybenzaldehyde $(CH_3OC_6H_4CHO)$.$1$. It contains an aldehyde group without $\alpha$-hydrogens,which allows it to undergo the Cannizzaro reaction with conc. $NaOH$ to form $p$-methoxybenzyl alcohol and sodium $p$-methoxybenzoate.$2$. It reacts with acetophenone $(C_6H_5COCH_3)$ in the presence of a base to undergo a cross-aldol condensation,forming a single product because the aldehyde lacks $\alpha$-hydrogens,ensuring it acts only as the electrophile.

$A$ compound of molecular formula $C_8H_8O_2$ reacts with acetophenone to form a single cross-aldol product in the presence of base. The same compound on reaction with conc. $NaOH$ forms benzyl alcohol as one of the products. The structure of the compound is

Similar Questions

In the given reaction sequence,the conversion of $B$ to $C$ is known as:

What will be the major product?

Give applications of cyanohydrins with acetaldehyde with suitable reactions. $OR$ Give following conversions by using acetaldehyde as starting material.
$(a)$ Lactic acid and acrylic acid
$(b)$ Alanine
$(c)$ $1$-amino propane-$2$-ol

What will be the compound $X$ in the given reaction?
$MeO-C_6H_4-CHO + (X) \xrightarrow{CH_3COONa, H_3O^+} MeO-C_6H_4-CH=CHCOOH$

Identify the pair of compounds which can be distinguished by the iodoform test.

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