A capacitor having a capacity of 2.0 ; mu F i | vedclass

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Question

(C) The energy stored in a capacitor is given by the formula $U = \frac{1}{2} C V^2$.Given:Capacitance $C = 2.0 \; \mu F = 2.0 	imes 10^{-6} \; F$Pot

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$4 	imes 10^{-2} \; J$

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(C) The energy stored in a capacitor is given by the formula $U = \frac{1}{2} C V^2$.Given:Capacitance $C = 2.0 \; \mu F = 2.0 	imes 10^{-6} \; F$Potential difference $V = 200 \; V$Substituting the values into the formula:$U = \frac{1}{2} 	imes (2.0 	imes 10^{-6} \; F) 	imes (200 \; V)^2$$U = 1.0 	imes 10^{-6} 	imes 40000$$U = 4 	imes 10^{-2} \; J$When the capacitor is discharged through a resistance wire,the entire stored energy is dissipated as heat. Therefore,the heat produced is $4 	imes 10^{-2} \; J$.

$A$ capacitor having a capacity of $2.0 \; \mu F$ is charged to $200 \; V$ and then the plates of the capacitor are connected to a resistance wire. The heat produced in joules will be:

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