The energy of a parallel plate capacitor when | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The energy stored in a capacitor is given by $E = \frac{1}{2} C V^2$.Since the battery remains connected,the potential difference $V$ across the p

Vedclass · Accepted Answer

$\frac{E}{2}$

Vedclass · Answer

(C) The energy stored in a capacitor is given by $E = \frac{1}{2} C V^2$.Since the battery remains connected,the potential difference $V$ across the plates remains constant.The capacitance of a parallel plate capacitor is $C = \frac{A \epsilon_0}{d}$,which implies $C \propto \frac{1}{d}$.If the distance $d$ is doubled $(d' = 2d)$,the new capacitance $C'$ becomes $C' = \frac{C}{2}$.The new energy $E'$ is given by $E' = \frac{1}{2} C' V^2$.Substituting $C' = \frac{C}{2}$,we get $E' = \frac{1}{2} (\frac{C}{2}) V^2 = \frac{1}{2} (\frac{1}{2} C V^2) = \frac{E}{2}$.

The energy of a parallel plate capacitor when connected to a battery is $E$. With the battery still in connection,if the plates of the capacitor are separated so that the distance between them is twice the original distance,then the electrostatic energy becomes

Similar Questions

Two capacitors of capacitance $2 \ \mu F$ and $4 \ \mu F$ are connected in series. If a potential difference of $10 \ V$ is applied across this combination,what will be the ratio of the energy stored in these capacitors?

$A$ cylindrical capacitor has charge $Q$ and length $L$. If both the length and the charge are doubled (keeping other parameters constant),the energy stored in the capacitor will:

$A$ parallel plate capacitor of capacitance $1 \ \mu F$ is charged to a potential difference of $20 \ V$. The distance between the plates is $1 \ \mu m$. The energy density between the plates of the capacitor is:

The energy stored in a capacitor is $W$. To double the charge on the plates of the capacitor,the additional work to be done is

If the charge on a body is increased by $2 \ C$,the energy stored in it increases by $21 \%$. The original charge on the body in coulomb is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module